Solution to 1992 Problem 43


Lagrange's equation is
\begin{align*}\frac{\partial L}{\partial q_n} = \frac{d}{dt} \frac{\partial L}{\partial \dot{q}_n}\end{align*}
The generalized momentum p_n is defined as
\begin{align*}p_n = \frac{\partial L}{\partial \dot{\theta}}\end{align*}
Therefore, if
\begin{align*}\frac{\partial L}{\partial q_n} = 0\end{align*}
then
\begin{align*}\frac{d p_n}{dt} = 0\end{align*}
Therefore, answer (B) is correct.


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